S
Sreeja
10 Jan 18 10:19 PM

HCF of two numbers is 24 and their LCM is 1344. If the difference between the number is 80 ,their sum is:

Replies to this post

A
Adarsh

Hcf x lcm=product of the numbers.
Let's the numbers be a and b. So ab=1344×24=32256. Let a=32256/b. As they given a-b=80. Put the value of a as 32256/b. Then we get 32256/b -b= 80. Simplify this equation so that 32256-b^2=80b. Make it as a quadratic equation as b^2+2b-32256=0. Solving this equation we can get 2 answers. And those answers are our numbers. So the numbers are 144 and 224. So the sum is 368.

1
M
Mahadev

But 224 is not a multiple of 24. Qn says 24 is a factor of the both the numbers

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S
Sreeja

Thankq

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