F
Fathimath
24 Apr 19

Pls give the ans fast....opt a can be correct since elongation under its own weight

Replies to this post

T
Theresa

Weight of rod=mg
Area=A
Stress= mg/A
Let change of length= l'
Original length=l
Strain= l'/l
Youngs modulus
Y= (mg/A)/(l'/l)
Y= mgl/Al'
l'=mgl/AY

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S
Shailja

Yes answer should be 1st....bcs under own weight we use avg of top and bottom points.....

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F
Fathimath

When such a question comes in which way do we have to approach

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