If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is covered completely into ammonia ,the ratio of initial and final volume under the same temperature and pressure would 1)3:1 2)1:3 3)2:1 4)1:2
1:3 I think so
3H2 + N2 =2 NH3. Therefore (3 x 22.4 L + 22.4. L ) required initially and obtained product has a volume of 2 x 22.4 L. Initial/final = (4 x 22.4)/(2 x 22.4) = 2:1