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Sudeeptvd

Anju, thanks for your reply. But can you explain steps in more detail .l fear l hadn't got your method.

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Anju

From the question you can find that the roots of the equation will be 1,2,3,...50

Coefficient of x^49 is a1.

You can use a trick here, consider(x-a)(x-b)= x^2- (a+b)x +b^2

Similarly

x^50-(1+2+3+4+.....49)x^49+....... will be the expansion. The coefficient of x^49 will be sum of 1 to 49

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Anju

The expansion will be x^50 +a1x^49+a2x^48+......+a49x+a50 =0

The roots of the equation are 1,2,3,4....50

a1 is the minus of the sum of roots of the equation.

a1=-(1+2+3+...50)

=-1275

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