How to solve question 29?
Anju, thanks for your reply. But can you explain steps in more detail .l fear l hadn't got your method.
The expansion will be x^50 +a1x^49+a2x^48+......+a49x+a50 =0
The roots of the equation are 1,2,3,4....50
a1 is the minus of the sum of roots of the equation.
From the question you can find that the roots of the equation will be 1,2,3,...50
Coefficient of x^49 is a1.
You can use a trick here, consider(x-a)(x-b)= x^2- (a+b)x +b^2
x^50-(1+2+3+4+.....49)x^49+....... will be the expansion. The coefficient of x^49 will be sum of 1 to 49