M
Madhurjya
18 Nov 17

Can someone help me with this question? Ques. No.-2 Answer is - c) 100√3 Js

Replies to this post

M
Mahadev

Angular momentum is the cross product of position vector and momentum vector

Angular velocity = Ux + Uy Ux = v cos 30 = 20 x √3/2 = 10√3 Uy = v sin 30 - gt = 20 x 1/2 - 10 = 0 Angular velocity = 10√3 + 0 = 10√3 Momentum vector = mass . Ang velocity = 2. 10√3= 20√3 i

Position vector = Xi + Yj X = Ux. t = 10√3 .1 = 10√3 Y= v sin 30. t - 1/2 g t^2 = 10-5 = 5 Moment of inertia = 10√3i + 5j Angular momentum = (20√3i ) X (10√3i + 5j ) = 100√3

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