M
Madhurjya
18 Nov 17 7:26 PM

Can someone help me with this question? Ques. No.-2
Answer is - c) 100√3 Js

Replies to this post

M
Mahadev

Angular momentum is the cross product of position vector and momentum vector

Angular velocity = Ux + Uy
Ux = v cos 30 = 20 x √3/2 = 10√3
Uy = v sin 30 - gt = 20 x 1/2 - 10 = 0
Angular velocity = 10√3 + 0 = 10√3
Momentum vector = mass . Ang velocity = 2. 10√3= 20√3 i

Position vector = Xi + Yj
X = Ux. t = 10√3 .1 = 10√3
Y= v sin 30. t - 1/2 g t^2
= 10-5 = 5
Moment of inertia = 10√3i + 5j
Angular momentum = (20√3i ) X (10√3i + 5j ) = 100√3

5