A person travels a certain distance at 3 km/h and reaches 15min late. If he travels at 4 km/h he reaches 15 min earlier. The distance he has to travel is?
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A certain distance at different speeds The distance travelled by that person,D=speed1×speed2/difference of speeds×time(if one is late and in next speed it is earlier then add the time otherwise subtract it) Here 3×4/4-3×30/60=12/2=6km