S
Sudeeptvd
06 Jun 18 7:15 PM

please answer q no 5

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R
Remya

Number of integers divisible by 2 between 1 and 100 can calculated as
100= 2+(n-1)*2
N=50
Sum of integers = n/2(2a+(n-1)d)
= 50/2(4+98)
= 2550
Similarly numbers divisible by 5
100= 5+(n-1)5
N=20
Sum = 20/2(10+95)
=1050
The numbers divisible by both 2 and 5=
100=10+(n-1)10
n=10
It's sum= 10/2(20+90)
There for the final required sum =2550+1050-550=3050

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