R
Ram
13 Jun 18 6:25 PM

Need explanation for the question no 102

Replies to this post

A
Amal

mutlitply and divide the given question by (2-1)..
{(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)}/(2-1)=
(2^2-1)(2^2+1)(2^4+1)(2^8+1)=
(2^4-1)(2^4+1)(2^8+1)=
(2^8-1)(2^8+1)=
2^16-1

0
A
Amal

using the identity (a+b)(a-b)=a^2-b^2

0