A
Abhijith
23 Oct 18 7:32 PM

Let x be the A.M. y , z be the two G.Ms between two positive numbers. Then [y^3 + z^3] / xyz =?

Replies to this post

A
Adithya

x=A+B/2
y=√Az
z=√By
y^3+z^3/xyz=y^3/xyz + z^3/xyz
=y^2/xz + z^2/xy = Az/xz + By/xy
=A+B/x = 2

2
A
Abhijith

Ohkk...,thnx dude.

0
Y
Yazeed

Let (a,b) be the to numbers
And AM=X==a+b/2
The two GM=Y=a^2/3 ×b^1/3
And. Z=a^1/3 ×b^2/3
Hence

Y^3+z^3=ab(a+b)
XYZ=ab (a+b)/2
Hence required answer=2

1