R
Let a->0,b->a; then a=b => a^2=ab => a^2-b^2=ab-b^2 => (a+b)(a-b)=b(a-b) => a+b=b => a=2b By applying limit b->a,
a=2a => 2=1. Prove the mistake?
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V
Vishnu
it is given that a=b , so a-b=0 in the step (a+b)=b(a-b)/(a-b) we get a division by 0 or in a 0/0 form which cannot be determined
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