A
Adithya
07 Nov 18

∫ dx / (√A²-x²) = ∫ ω dt  sin -1 x/A = ωt How?

Replies to this post

C
Calvin

Integral of 1/√(A^2-x^2)= sin^-1(X/A)

2
{
{🅰t!-!ℹ®🅰}=💯

Integral of 1/√(A^2 -X^2)=sin^-1(X/A)
I think this is the answer🤔

2