Q. What is the equation for harmonic frequency imposed on the AC line of a cycloconverter ?

A
fh = f1 (k/q +-1) +- 6nfo
B
fh = f1 (k+q +-1) +- 6n/f0
C
fh = f1 (kq?1) ? 6nfo
D
fh = f1 (kq+-1) +- 6n/f0
Solution:

fh = harmonic frequency imposed on the AC line
k and n = integers q = pulse number (6, 12 . . .)
fo = output frequency of the CCV
Equation’s 1st term represents the pulse number converter harmonic components starting with six-pulse configuration
Equation’s 2nd term denotes the converter’s sideband characteristic frequencies including associated interharmonics and subharmonics.

Entri Contact Image

Get Expert Advice for Free: Register for Your Free Consultation Now!