Solution:

• Radial node is a spherical surface where the probability of finding an electron is zero.
• The equation for finding radial node is n-l-1.
• Angular node is a plane that passing through the nucleus. Angular node is equal to the azimuthal quantum number (l).
• In a 4f orbital, the principal quantum number is 4 and the angular quantum number is 3 (n=4,l=3).
• Therefore, the number of angular nodes present in 3.
• Here, the value of n will be 4. This means there will be no radial nodes present in 4f orbital.