Q. A boat loaded with rocks floats in the middle of a swimming pool. A man in the boat throws the rocks overboard. The level of water in the pool will
Solution:
Let M and m grams be the mass of boat + rock in it. By law of floatation(M+m) grams of water will be displaced. This has a volume of (M+m)cc. That means the level of water in pool has risen up by (M+m)cc with the boat + rock when it is floating. If the rocks in the boat are thrown not into the pool but outside, the weight left is only M grams the weight of the boat. This will have displaced M cc of water only i.e less water than in the case of loaded boat. But if the rocks are put in the water in the pool and not outside, then the water in the pool will rise not only by M cc on account of empty boat but also by a volume of the stone put into it. This volume will be md where m is the mass of rock and d density of rock.
Now md is < m. Thus the total rise will be (M+md)which is < M + m.
Related Questions
Q. When a brick put in to the water it absorbs water quickly. Identify the phenomenon behind this
View SolutionQ. The source of energy which are formed in earth over millions of years and which get deleted due to their continuous use but do not replenished are known as
View SolutionQ. Substance used for producing heat energy are called
View Solution
Get Question Bank
Strengthen Your Practice with our comprehensive question bank.
