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When no base voltage is present, the switch is off. When base voltage is present, the switch is on. Transistor will be in OFF ( cutoff ) when the input Vin equal to zero.

The current gain for the common-base configuration is defined as the change in collector current divided by the change in emitter current when the base-to-collector voltage is constant. Typical common-base current gain in a well-designed bipolar transistor is very close to unity.

The transistor can be used as a switch if biased in the saturation and cut-off regions. This allows current to flow (or not) in other parts of a circuit. Because a transistor’s collector current is proportionally limited by its base current, it can be used as a sort of current-controlled switch.

There are totally 6 registers, in an 8086 microprocessor. Th)o become set (1) or reset (1) depending upon certain condition. Only status register will have 8086 flags.

The power of the input signal is increased to a level high enough to drive loads of output devices like speakers, headphones, RF transmitters etc.

The Class B amplifier circuit above uses complimentary transistors for each half of the waveform and while Class B amplifiers have a much high gain than the Class A types, one of the main disadvantages of class B type push-pull amplifiers is that they suffer from an effect known commonly as Crossover Distortion.

The steady state operation of a transistor depends a great deal on its base current, collector voltage, and collector current values and therefore, if the transistor is to operate correctly as a linear amplifier, it must be properly biased around its operating point.

Nodes are the point by which the branches are outgoing or ingoing and this can be input or output node and input node is the node having only outgoing branches

The table given below gives the required details.

Thus the output is 101.

Divide by 4, that is 128/4 = 32
32/4 = 8
8/4 = 2
2/4=.5
Thus Number of MUX needed= 32+8+2+1=43.

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