Q. The base emitter voltage in a cut off region is_

A
greater than 0.7 V
B
equal to 0.7 V
C
less than 0.7 V
D
cannot be predicted
Solution:

From the cut off characteristics, the base emitter voltage (VBE) in a cut off region is less than 0.7V. The cut off region can be considered as ?ff mode?Here, VBE > 0.7 and IC=0. For a PNP transistor, the emitter potential must be negative with respect to the base.

Entri Contact Image

Get Expert Advice for Free: Register for Your Free Consultation Now!