# Hexaware aptitude questions

The Hexaware recruitment exam is a tough nut to crack. To prepare for it, aptitude questions and answers should be a must in your study plan. If you practice the aptitude questions and answers well, you will improve your score and thus your chances of getting selected. In this article, we will discuss a few aptitude questions and answers for the Hexaware recruitment exam. Have a Look Now!

1. The square root of the sum of two consecutive integers is 7. Find the two integers?

• Let first number be x

So second number = x + 1

So, as per question,

$\sqrt{x+x+1}$ = 7

$\sqrt{2x+1}$ = 7

• Now, on squaring both sides.

$2x+1 = 49$

$2x = 49-1$

x =$\frac{48}{2}$

$x =24$

• So the two integers are 24 and 25

1. Walking at $\frac{4}{5}$ of his usual speed, a man covers a distance 9 min late. Find his usual time to cover the journey ?

• $\frac{4}{5}$th of his usual speed leads 9 min late

• Speed is inversely proportional to time.

• Then time = $\frac{5}{4}$ of usual time

• Hence change in time= $\frac{5-4}{4} \times$ usual time = 9 min
Hence usual time= $4 \times 9 =36$

1. The teacher was 15 minutes late when traveling at 4km/hr to school. She arrived 15 minutes early the next day at 5km/hr. So what is the distance from school to home?

• Distance =$\frac{a\times b} {a-b}$$\times$ Time gap

• a = Higher speed , b = Lower speed

• a = 5km/hr, b = 4km/hr,

• time gap= 15 +15 = 30 minutes

• 30 minutes= $\frac{30}{60}$hr

• Distance=$\frac{5\times 4}{5-4}\times\frac{30}{60}$

• $\frac{5\times4}{1}\times\frac{30}{60}$ = 10 km

1. A boat moves downstream at the rate of 2 km in 12 minute and upstream at the rate of 1 km in 10 minute. Find the time taken by boat to covers 3 km in still water.

• Downstream speed=$\frac{2}{12}$x60=10 km/hrs
• Upstream speed=$\frac{1}{10}$x60=6 km/hrs

Speed of boat in still water $\frac{10+6}{2}$=8 km/hrs

• Required times= $\frac{3}{8}$x60=22.5 minutes
1. Find the Simple interest on Rs 12000 for 3 years at 12% interest rate:

• Simple interest = $I= \frac{PNR}{100}$
• $I= \frac{12000 \times 3 \times 12}{100}=120 \times 3 \times 12=4320$
• Answer is $4320$.