MU Sigma aptitude questions

One of the most important skills in getting hired for any job is the ability to ace the aptitude test. For anyone applying for a job at Mu Sigma, it is important to be well-prepared for their aptitude tests, as they are one of the key components of their recruitment process. Here are a few questions and answers to prepare for the upcoming Mu Sigma Recruitment Exam.

1. If a land is harvested by 4 men or 8 women or 12 boys in 11 days .How many days will be taken by 2 men , 6 women and 4 boys to harvest the same field.

• 4 men = 8 wome = 12 boys

• 1 man = 2 women = 3 boys

• 2 men + 6 women + 4 boys = 2 x 3 boys + 6$\times$ $\frac{3}{2}$ boys + 4 boys = 19 boys

• 12 boys can harvest in 11 days

• 19 boys can harvest in $\frac{11\ \times \ 12}{19}$ = $\frac{132}{19}$days

1. The ratio between the present age of $P$ and $Q$ is $6:7$.If $Q$ is $4$ years old than $P$ what will be the ratio of ages of $P$ and$Q$ after$4$ years

• P = 6x , Q = 7x $7x-6x=4$

$x=4$

• Present ages are $24,28$

age after $4$ years is $28,32$

• So the ratio will be $7:8$

1. A train 240 m long is running at a speed of 98 km/h. In what time will it pass a man who is running at a speed of 10 km/h in the opposit direction?

• Distance= 240 m

Relative speed(opposit direction)=$S_{1}+S_{2}$=98+10=108 km/h

• Convert into m/sec

$108\times\frac{5}{18}$=30 m/s

Time=$\frac{Distance}{Speed}$

=$\frac{240}{30}$= 8 sec

1. The simple interest on a certain sum of money for 2 year at 3% pa is $\frac{3}{4}$ of the compound interest on Rs. 32000 for 1 year at 3% pa. Find the sum placed on simple interest?

• compound interest for 1 year=$32000\times\frac{3}{100}=960$

SI for 2 year=$960\times\frac{3}{4}=720$

720=$sum\times\frac{3}{100}\times2$

• Sum=12000

1. $\frac{(18+0.5)^2-(18-0.5)^2}{0.5}=?$
• $(a+b)^2-(a-b)^2=4ab$
• $\frac{(18+0.5)^2-(18-0.5)^2}{0.5}=\frac{4\times18\times0.5}{0.5}$
$4\times18=72$