Mindtree aptitude questions

• Percentage difference <br> 20% - 12% ⟹ 24

  8% ⟹ 24

  The number is 100%.

  8% ⟹ 24 <br> 100% ⟹ ?

• To find the number, simply cross-multiply them and then divide them as shown below.

• 

• The number = \(\frac{24 \times 100}{8}\)= 300

• Average = \(\frac{n+1}{2}\)

• \(\frac{111+1}{2}\) = \(\frac{112}{2}\) = 56

• Answer is 56.

• Given \(\sqrt{3} ×\sqrt{12} ×\sqrt{27} ×\sqrt{48}\)

• \(\sqrt{3} ×\sqrt{12} ×\sqrt{27} ×\sqrt{48}\) =\(\sqrt{3} ×\sqrt{4 × 3} ×\sqrt{9 × 3} ×\sqrt{16 ×3}\)

  =\(\sqrt{3} ×2\sqrt{3} ×3\sqrt{3} ×4\sqrt{3}\)

  = \( 24 × 3 × 3 \)

  = \( 216 \)

• Answer is 216

• Percentage of girls = 100 - 60 = 40%

  40% = 500

  60% = \(x\)

  \(x\times40 = 500\times60\)

  \(x\) = \(\frac{500\times60}{40 }\) = 750

  Number of boys = 60% = 750.

• Easy method :

  Boys are 60%.

  Percentage of girls = 100 - 60 = 40%

  40% = 500

  60% =?

• To find the number of boys, just multiply them crosswise and divide them as shown below.

  

• Number of boys = \(\frac{500\times 60}{40}=750\)

• Let X is the sum.

• SI=\(\frac{x \times6\times5}{100}=1635\)

  x = \(\frac{163500}{30}=5450\)

• Answer is 5450.

• b is in mean proportion to a and c, so \( \frac{a}{b} = \frac{b}{c} \) = k

• a = bk and b = ck

  \( \frac{ (a-b)^{3} }{ (b-c)^{3} } \) = \( \frac{ (bk-b)^{3} }{ (ck-c)^{3} } \) = \( \frac{ b^{3} }{ c^{3} } \)

  But, \( \frac{a}{b} = \frac{b}{c} \)

• \( \frac{ (a-b)^{3} }{ (b-c)^{3} } \) = \( a^{3} \) : \( b^{3} \)

• Let weigth be 10 gm

• Price = 10\( ^{3} \) = 1000

• Weigth of their pices = 3 : 4 : 3

• Their values = 3gm, 4gm, 3gm

• Their prices = 3\( ^{3} \) + 4\( ^{3} \) + 3\( ^{3} \)

  =27+64+27=118

  Difference =1000-118=882

  % of difference = 882/1000 x 100 = 88.2%

• First year interest=\(3500\times\frac{6}{100}=210\)

• Second year interest=\(3500+210\times\frac{6}{100}=222.6\)

• Total interest=210+222.6=432.6

• We know that

  average speed =\( \frac{2xy}{x+y} \)

• now ATQ,

  average speed =\( \frac{2 \times 36 \times 24}{36+24} \)

  =\( \frac{72 \times 24}{60} \)=28.8 km/hr

• Answer is 28.8 km/hr.

• Total age of father and mother =\( 38×2= 76 \)

• Total age of father, mother and daughter =\( 28×3= 84 \)

• Therefore age of daughter =\( 84−76= 8 \)

• Distance =\(\frac{s_{1}\times s_{2}}{s_{1}−s_{2}}\ \) \( \times \) differenceintime

• Convert 15 minutes into hour.

  =\(\frac{12\times 8}{12−8}\times\frac{15}{60}\)

  =\(\frac{12\times 8}{4}\times\frac{1}{4}=6km\)

• Answer is 6 km

• Speed of Emin =120m/12 sec=10m/sec

• Distance completed by Emin in 8 seconds=\(speed\times time =10\times8=80\) meter

• Answer is 40 meter.

Remaining distance to finishing point=120-80= 40 meter

• Sum of n consecutive odd numbers =\(n^{2}\)

  sum of first 45 odd numbers =\(45^{2}\)=2025

• Sum of n consecutive even numbers =n(n+1)

  sum of first 45 even numbers =45(45+1)= \(45\times46\)=2070

• difference =2070-2025=45

• \((a+b)^{2}=a^{2}+b^{2}+2ab\),

• Question show the format,\(a^{2}+2ab+b^{2}\)

  \(6.4\times6.4+2\times55.04+8.6\times8.6 =(6.4+8.6)^{2}\)

  =\(15^{2}=225\)

• Answer is 15.

• Work done by tap A in one hour = \( \frac{1}{50} \)

• Work done by tap B in one hour = \( \frac{1}{60} \)

• Work done by tap C in one hour =\( \frac{1}{75} \)

• Work done if all the three taps are opened together = \( \frac{1}{50} \) + \( \frac{1}{60} \)+ \( \frac{1}{75} \) \( = \frac{6+5+4}{300} = \frac{15}{300} = \frac{1}{20} \)

• Time taken to fill the tank if all of them are opened together =\( \frac{1}{\frac{1}{20}} = 20 \) hours

• A can fill the tank in 10 hours

  A's one hour work = \( \frac{1}{10} \)

• B can fill the tank in 12 hours

  B's one hour work = \( \frac{1}{12} \)

• C can fill the tank in 15 hours

  C's one hour hour work = \( \frac{1}{15} \)

  Then (A + B + C)'s one hour work = \( \frac{1}{10} \)+\( \frac{1}{12} \) + \( \frac{1}{15} \)= \( \left ( \frac{6+5+4}{60}\right ) \) = \( \frac{1}{4} \)

• Hence, (A+B+C) can fill the tank in 4 hours.

• Speed downstream = (15 + 6) km/hr = 21 km/hr.

• Time taken to travel 84 km downstream hrs=(\( \frac{84}{21} \))=4hrs

• Answer is 4 hours.

• A’s 2 days work = B’s 3 days work

• \( \therefore \) Time taken by A = 8 days

• \( \therefore \) Time taken by B =\( \dfrac{8}{2} \times 3 = 12 \)days

• Ratio = 11x : 6x

  Five years ago (11x - 5) = 2(6x -5)

  11x - 5 = 12x - 10

  x = 5

  So, the age of mom = 55 and age of son = 30

• From 20 years, mom = 75 and son = 50

  So, Son's age will the Mother's age be twenty years from now will be 1.5 times

• Answer is 1.5 times.

• \(\sqrt{56+\sqrt{56+\sqrt{56+....}}}\) = x

• x² - 56 -x = 0

  (x - 8)(x + 7)

• x = 8 (Take the largest number in the case of addition )