Table of Contents
The 15th edition of the CTET examination will be conducted online by the Central Board of Secondary Education (CBSE) from 16th December 2021 to 13th January 2022. CTET is a national level examination to recruit teachers for primary & elementary stages.
There will be two papers for CTET exam:
- Paper I will be for teachers of classes 1 to Class 5 i.e. Primary Stage.
- Paper-II will be for teachers of classes VI to Class VIII i.e. Secondary Stage.
CTET Exam Maths Paper 1 and Paper 2
The CTET exam is conducted based on the CTET syllabus prescribed by the CBSE. There will be 30 questions of 1 mark each in Mathematics section of Paper 1 and Paper 2. There will be no negative markings for incorrect answers. The syllabus for CTET 2021 Maths Paper 1 and CTET 2021 Maths Paper 2 is given below.
The syllabus for CTET 2021 Maths paper 1 is as follows:
Content
- Geometry
- Shapes & Spatial Understanding
- Solids Around Us
- Numbers
- Addition and Subtraction
- Multiplication
- Division
- Measurement
- Weight
- Time
- Volume
- Data Handling
- Patterns
- Money
Pedagogical Issues
- Nature of Mathematics/Logical Thinking; Understanding Children’s Thinking and Reasoning Patterns and Strategies of Making Meaning and Learning
- Place of Mathematics in the Curriculum
- Language of Mathematics
- Community Mathematics
- Evaluation through Formal and Informal Methods
- Problems of Teaching
- Error Analysis and Related Aspects of Learning and Teaching
- Diagnostic and Remedial Teaching
The syllabus for CTET 2021 Maths paper 2 is as follows:
Content
1. Number System
- Knowing our Numbers
- Playing with Numbers
- Whole Numbers
- Negative Numbers and Integers
- Fraction
2. Algebra
- Introduction to Algebra
- Ratio and Proportion
3. Geometry
- Basic Geometrical Idea (2-D)
- Understanding Elementary Shapes (2D and 3D)
- Symmetry (Reflection)
- Construction (Using Straight Edge Scale, Protractor, Compasses)
- Mensuration
- Data Handling
Pedagogical Issues
- Nature of Mathematics/Logical Thinking
- Place of Mathematics in Curriculum
- Language of Mathematics
- Community Mathematics
- Evaluation
- Remedial Teaching
- Problem of Teaching
CTET Questions With Answers
The numbers of boys and girls in a college are in the ratio of 3:2. If 20% of the boys and 25% of the girls are adults, the percentage of students, who are not adults, is:
- 58%
- 60(1/5)%
- 78%
- 83(1/3)%
Ans: 3
Explanation:
Let the total number of boys and girls be 100
Ratio of Boys : Girls = 3 : 2 -> Sum of ratio terms = 3 + 2 = 5
Numbers of boys = (3/5) x 100 = 60
Number of girls = (2/5) x 100 = 40
Number of adults = (60 x 20)/100 + (40 x 25)/100 = 12 + 10 = 22
The number of students who are not adults = 100-22=78
Percentage of student, who are not adults = 78 %
In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.
- 40%
- 41%
- 43%
- 44%
Answer: 4
Explanation:
Number of students who failed in mathematics, n(1) = 34
Number of students who failed in English, n(2) = 42
n(AUB) = n(1) + n (2) – n (A∩ B )
= 34 + 42- 20 = 56
Number of students who failed in either one or both the subjects = 56
Pass percentage = (100−56)%=44%
4 men can complete a piece of work in 2 days. 4 women can complete the same piece of work in 4 days whereas 5 children can complete the same piece of work in 4 days. If 2 men, 4 women and 10 children work together, in how many days can the work be completed?
- 1 day
- 3 days
- 2 days
- 4 days
Ans: 1
Explanation:
4 men × 2 = 4 women × 4 = 5 children × 4
2 men + 4 women + 5 children = 4 women x 4 = 16 women x 1 = 1 day
Imran borrowed a sum of money from Jayant at the rate of 8% per annum simple interest for the first four years, 10% per annum for the next six years and 12% per annum for the period beyond 10 years. If he pays a total of Rs. 12,160 as interest only at the end of 15 years, how much way did he borrow?
- 8000
- 10,000
- 12,000
- 9,000
Ans: 1
Explanation:
Let the principal be Rs. P
(P x 8 x 4)/100 + (P x 10 x 6)/100 + (P x 12 x 5)/100 = 12160
152P = 12160 × 100
P = (12160 X 100) / ( 152) = Rs. 8000
The question below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the questions. Give answer –
- The data in statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question.
- The data in statement II alone is sufficient to answer the question, while the data in statement I alone is not sufficient to answer the question.
- The data either in statement I alone or in statement II alone is sufficient to answer the question.
- The data in both the statements I and II together are necessary to answer the question.
Ans: 4
Explanation:
With the help of both statement I and II, the odd number can be found.
CTET Questions PDF Download
You can download CTET previous year’s papers PDF in both Hindi and English. Solving previous years’ papers helps the candidates to assess and analyze their preparation and skill and also gives an idea of frequently asked questions or topics.
The CTET paper 1 is conducted from December 16 to January, 2021 to January 13, 2022. As t is an online exam, candidates will not get a copy of the question paper after the exam.
CTET Question Paper Analysis 2021
Benefits of Solving CTET Previous Year Papers
- It helps in time management.
- It helps to understand the exam pattern and marking scheme.
- It helps to analyze one’s strength and weaknesses.
- It helps to understand the sectional weightage of examination.
- Candidates get to know about the important questions and topics.
- It enhances one’s preparations and boosts the confidence level.
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