Tech mahindra aptitude questions

• Interest for 5 year=1368

• Interest for 1 year=6% of borrowing=\(\frac{1368}{5}=273.6\)

• 100% of borrowing=\(\frac{273.6}{6}\times 100=4560

• Odd numbers between 73 and 187 is 75,77,......,185.

• Average = \(\frac{75+185}{2}\)

  = \(\frac{260}{2}\) = 130.

• Answer is 130.

• Average of first \(n\) odd numbers = \(n\)

• Average of first 321 odd numbers = 321

• Answer is 321.

• \(A \rightarrow \)125, \(B\rightarrow 100\)

  B's salary is 25 rupees less than A's salary.

  \(\frac{25}{125}\times100=20\)% less.

• Easy Method :

  Take B's salary as 100

  Then the salary of A is 125

• In such questions, first write as follows

  

  B's salary is 25 rupees less than A's salary.

• Divide the difference 25 by the non-100 number 125. Then multiply by 100

  \(\frac{25}{125}\times100=20\)% less.

• one day's 12 H + 16 B = \( \dfrac{1}{5} \) = 60 H + 80 B

• one day's 13 H + 24 B = \( \dfrac{1}{4} \) = 52 H + 96 B

• comparing both the equation, we get

  \( \Rightarrow \) 60H + 80B = 52H + 96B

  \( \Rightarrow \) 8 H = 16 B

  \( \Rightarrow \) \( \dfrac{H}{B}= 2:1 \)

• 5\(\sqrt{3}\) = (\(5\sqrt{3})^{2}\) = 75

• 4\(\sqrt{2}\) = (\(4\sqrt{2})^{2}\) = 32

• 7\(\sqrt{1}\) = (\(7\sqrt{1})^{2}\) = 49

• 2\(\sqrt{5}\) = (\(2\sqrt{5})^{2}\)= 20

• So,the answer is 75 =5\(\sqrt{3}\).

• We know that,

  \(\sqrt{x\sqrt{x\sqrt{x.......}}}\) =x

• \(\sqrt{105\sqrt{105\sqrt{105.......}}}\) =105

• Answer is 105

• Speed of boat downstream (B + C) = \( \frac{32}{4} \) = 8km/h

• Speed of boat upstream (B - C) =\( \frac{40}{8} \) = 5km/h

  2B = 13 km/h

  B = 6.5 km/h

• Answer is 6.5 km/hr.

• Rate =X

• Then,\(\frac{3000\times x \times2}{100}+\frac{4000\times x \times5}{100}=1560\)

  60 x +200 x=1560

  x=\(\frac{1560}{260}=6\)

• Rate=6%

• Answer is 6%.

• Total age of father and mother =\( 38×2= 76 \)

• Total age of father, mother and daughter =\( 28×3= 84 \)

• Therefore age of daughter =\( 84−76= 8 \)

• Field is sufficient for 24 horses \( ( 28 - 11 ) = 17 \) days

• Number of horses along with new horses \( = 24 + 10 = 34 \)

• Required number of days = \( \dfrac{24 \times 17}{34} \) = 12 days

• Let the speed of water is W

  His upstream speed = 36-W

• According to question

  (36-W) X(1+\( \frac{3}{4} \))=56

  36-W = 32

  W = 36 - 32 = 4 km /h

  His downstream speed = 36+W

  T =\( \frac{56}{36+4} \) = 1 hr 24 minutes

• Answer is 1hr 24min.

• \((a+b)^2=a^2+2ab+b^2\)

• \((\sqrt{0.5}+\sqrt{50})^2=(\sqrt{0.5})^2+(2\times\sqrt{0.5}\times\sqrt{50})+(\sqrt{50})^2\)

  =0.5+10+50=60.5

• Answer is 60.5.

• Pipe A can fill a tank in 10 hours

  Part of the tank A can fill in 1 hour = 1/10

• Pipe B can fill a tank in 12 hours

  Part of tank B can fill in 1 hour = 1/12

• Pipe C can empty the tank in 6 hours

  Part of the tank C can empty in 1 hour = 1/6

• Part of tank can filled in 12 hours when all three pipes are opened

  \( \left ( \frac{1}{10} +\frac{1}{12}-\frac{1}{6}\right ) = \left ( 6+5-10\right )60 \times 12 = \frac{12}{60} = \frac{1}{5} \)

• Time taken to cover the train length(T)=17 sec

• Time taken to cover the train length + 32 meter platform=25 sec

  25-17= 8 sec, is taken to pass the 32 meter platform

  Speed=32 m/8 sec =4 m/s

• Distance/Length of train=\(Speed\times Time\)=4×17=68 meter

• If we take the number as \(x \), then half of the number is \(\frac{x}{2}\) <br>

  \( x \times \frac{39}{100} + 88\) = \(\frac{x}{2} \)

  \( \frac{39x}{100} + 88\) = \(\frac{x}{2} \)

  \(\frac{x}{2} \) - \( \frac{39x}{100}\) = 88

  \(\frac{50x-39x}{100} \) = 88

  \(\frac{x \times11}{100} \) = 88

  That is, 11% of x is 88 <br>

• 11% \( \rightarrow\) 88 <br> 20 % \(\rightarrow\)?

• 20% of the number = <br>

  \(\frac{88\times 20}{11} \)= 160

Easy Method :

• Suppose the number is \( x \).

  Adding 39% of \( x \) to 88 gives half of that number.

  That is, half of \( x \) gets \( \Rightarrow\) 50% of \( x \)

  39% + 88 = 50% of \( x \)

  \( \Rightarrow\) 88 = 11%

  11% \( \rightarrow\) 88 <br> 20 % \(\rightarrow\)?

• To find 20% of the number, just multiply them crosswise and divide them as shown below.

  

• 20% of the number \( \Rightarrow\) \(\frac{88\times 20}{11} \)= 160

• Ratio=\(\frac{\frac{P\times r \times3}{100}}{\frac{P\times r \times12}{100}}\)=\(\frac{3}{12}\)

• Ratio=1:4

• Answer is 1:4.

• Let MP = 100%

  Discount = 22% ⇒ SP = 78%

  ie, 78% = 390

• 100% = \(x\)

  \(x\times78 = 390\times100\)

  \(x\) = 500

• Therefore, MP = 100% = 500.

• Ratio = 11x : 6x

  Five years ago (11x - 5) = 2(6x -5)

  11x - 5 = 12x - 10

  x = 5

  So, the age of mom = 55 and age of son = 30

• From 20 years, mom = 75 and son = 50

  So, Son's age will the Mother's age be twenty years from now will be 1.5 times

• Answer is 1.5 times.

• Let MP = 100%

  Discount = 30% \(\Rightarrow\) SP = 70%

  ie, 70% = 560

  1% = 8

• Therefore, MP = 100% = 8 \(\times 100\) = 800.

• Answer is 800.