TNPSC Maths Questions with Solutions

Table of Contents

The Tamil Nadu Public Service Commission issues the TNPSC Exam Recruitment exam to shortlist eligible candidates who expect to join the Tamil Nadu public service. Candidates for different Group service positions are chosen both with and without an interview.

Aptitude and Mental Ability questions are more important for TNPSC Group Exam. You will earn 25 marks from that Aptitude and Mental Ability portion easily with good preparation. Students who are training for the TNPSC exam focus more on the maths part. You will effortlessly score more marks in the Mental Ability part.

TNPSC Aptitude and Mental Ability Main Topics:

Conversion of information to data -collection, compilation, and presentation of data ‐ Tables, graphs, diagrams‐Parametric representation of data‐Analytical interpretation of data
Simplification
Percentage
Highest Common Factor (HCF)
Lowest Common Multiple (LCM)
Ratio and Proportion
Simple interest, Compound interest
Area‐Volume
Time and Work
Behavioral ability ‐ Basic terms
Communications in information technology
Application of Information and Communication Technology (ICT)
Decision making and problem-solving

Logical Reasoning:

Puzzles
Dice
Visual Reasoning
Alphanumeric Reasoning
Number Series Logical Number/Alphabetical/Diagrammatic Sequences

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TNPSC Maths Questions and Solutions

Here we added some previous years’ questions and solutions for the good awareness of question patterns.

Paulson pays 75 of his income. His income is growing by 20 and he increased his

charges by 10. Find the Chance growth in his savings.

(A) 27

(B) 50

(D) 28

Answer (B) 50

Result

Let us take income = 100

Expenditure = 75

Increase in income = 20

So, the increase income = 120

Before saving = 25

Increased total saving = 37.5

So increased saving = (new saving – old saving) = (37.5-25) = 12.5

Chance increased in saving = 12.5/ 25 * 100 = 50

what is the straightforward interest earned on Rs. invested 3 months at a rate of fifty per

. time?

(A)Rs. 250/-

(B)Rs. 100/-

(C)Rs. 125/-

(D)Rs. 500/-

Answer (A)Rs. 250/-

Result

P = 20000

R = 5

SI = Rs. 250/-

x3 x2 – 7x – 3 is resolve by x – 3 also the worth if remainder is

(A) 16

(B) 14

(D) 13

Answer (C) 12

Result

Givenx-3 = 0

Also x = 3

Cover x = 3 in eqn-7x-3 = 0

2721-3 = -12

So the remainder is 12.

What chance of figures from 1 to 50 having 0 or 5 within the unit’s number?

(A) 5

(B) 10

(D) 20

Answer (D) 20

Result

were the figures having 0

were the figures having

. Total figures having 0 and 5 = 10

Total figures from 1 to 50 = 50 figures = 100

In a two number, the sum of integers is 11. If the integers are reversed also the new number is 9 lower than the given number. The given number is

(A) 47

(B) 29

(D) 65

Answer (D) 65

Result

65 = 6 5 = 11

When reversed 65 it will give 56 and it’s but 65 by 9.

So the answer is 65.

A man earns Rs. 20 on the first day and spends Rs. 15 on a coming day. He again earns Rs. 20 on the 3rd day and spends Rs. 15 on the fourth day. However, how soon will he have Rs, If he continues to save like this? 60 in hand?

(A) On the 17th day

(B) On the 22nd day

(D) On the 40th day

Answer (A) On 17th-day

result

for 2 days he’ll haveRs. 5 in hand

for 16 days =

On 17th day he’ll have the payment of 20Rs = 40 20 = 60 8. Angles of a triangle are within the rate 1 2 3 also Triangulum is

(A) Equilateral Triangle

(B) Isosceles Triangle

(D) Isosceles Right Angled Triangle Answer (C) Right Angle Triangle

result

123 = completely 6 corridors

6x = 180 thus x = 30 x 2x 3x = so it’s right-angled triangle.

In a family, the father took of the cutlet, and he’d 3 times as much as each the other members had. The total number of family members is

(A) 3

(B) 7

(D) 12

Answer (C) 10

Result

Father had 1 part in total 4 corridor = = (1-) = 3 corridor remaining in 4 corridors.

and it’s 3times as family members = 3 * 3 = 9 members so completely (9 members 1 father) = 10 members.

an oblong yard3.78 measures long and5.25 metres wide is to be paved exactly with square penstocks, all of original size. What’s the most important size of the pipe which might be used for the purpose?

(A) 14 cms

(B) 21 cms

(D) None of these

Answer (B) 21 cms

result

3.78 m = 378 cm = 2 * 3 * 3 * 3 * 75.25 m = 525 cm = 5 * 5 * 3 * 7 common factors = 3 * 7 = 21 cms.

A sector of 120 °, cut out from a circle, has an area of 9sq.cm. Find the compass of the circle

(A) 1 cm

(B) 2 cm

(D) 3 cm

Answer (D) 3 cm

result

r =

r = 3 cm

A field is in the form of a cube having its sides in portion 2 3. The area of the field is hectares. Find the length of the field.

(A) 40 m

(B) 33 ½ m

(D) 45 m

Answer (C) 50 m

Result

Length = 2x

Breadth = 3x

A =

2x * 3x =

To find length = 2x = 2 * m

By dealing with 33 measures of cloth, one gains the selling price of 11 measures. Find the gain percent.

(A) 25

(B) 30

(D) 50

Answer (D) 50

Result

( dealing price of 33m) – ( cost price of33m) = GAIN

For each metre Rs. 1

Selling price of 22m = Rs 33

gain = * 100 = 50

Find the least number which when divided by 6, 7, 8, 9, and 12 leaves the same remainder 1 in each case (A) 504

. (B) 505

(D) 167

Answer 505

Result

When there’s memorial 1 the number which ends with indeed integers won’t come because multiplying indeed figures with bot odd and indeed figures will come s indeed only. So 504 won’t come.

The figures 253and 167 aren’t separable by 7 and 9.

The number 505 is separable be all the figures and leaves the remainder 1.

The Business Lights at three different road crossings change after every 48 sec, 72 sec and 108 sec especially. However, also at what time will they again change contemporaneously?

, If they all change contemporaneously at 8 20 00 hours. (A) 8 20 48 hrs

(B) 8 21 12 hrs

(D) 8 27 12 hrs

Answer (D) 8 27 12 hrs

result

L.C.M OF 48, 92, 108 48 = 2 * 2 * 2 * 2 * 3

.92 = 2 * 2 * 2 * 3 * 3 108 = 2 * 2 * 3 * 3 * 3L.C.M = 432 secs

7 mins 12 secs

Add 7 mins 12 secs to 8 20 00 it’ll come as 8 27 12 hrs

Find the missing number 5, 4, 8, 9, 11, 14, 14,,

. (A) 19

(B) 17

(D) 16

Answer (A) 19

Result

5, 4, 8, 9, 11, 14, 14

. The figures 5 (1st), 8 (3rd), 11 (5th), 14 (7th) has the difference 3.

The figures 4 (2nd), 9 (4th), 14 (6th) has the difference 5.

So the 8th place = 6th place 5 = 14 5 = 19

If √ 2116 = 46 also value of √21.16 √0.2116 √0.002116

(A)5.106

(B)5.116

(D)5.221

Answer (A)5.106

Result

√21.16 = 4.6

√0.2116 = 0.46

√0.002116 = 0.046

4.60.460.046 = 5.106

A can do a certain job in 12 days. B is 60 further effective than A. How numerous days does B alone take to do the same job?

(A) 8 days

(B) 7 days

(D) 8 days

Answer (C) 7 days

result A = 12 days B = 60 more effective than A = 1.6

Leela reads a book in 1 hour. How important of the book will she read in 3 hours?

Part

(D) Whole Book

Answer (B) Part

11, 16, 24, 35, 49, ?

. (A) 62

(B) 63

(D) 66

Answer (D) 66

11, 16, 24, 35, 49?

. (A) 62

(B) 63

Result

11, 16, 24, 35, 49

.16-11 = 5

24 – 16 = 8

24 – 35 = 11

49 – 35 = 14

The difference between each number is 3.

To find the coming number add 3 14 = 17 add this 17 to 49 = 17 49 = 66

The number of nags on a ranch is twice the number of ducks. The total number of bases of ducks and nags counted together is 70. The number of ducks is

(A) 5

(B) 7

(D) 35

Answer (B) 7

Result

Steed = y and duck = x

Steed = 2 times of duck

Y = 2x

Ducks hs 2 bases and steed hs 4 bases

2x 4y = 70

Sub y = 2x in above equation

2x 4 (2x) = 70

2x 8x = 70

10x = 70

X = 7

Also sub x = 7 in y = 2x y = 2 (7) y = 14 (steed)

At present Abi is doubly as old as Reeta. After seven times their age difference is 5 times. The present age of Reeta is

(A) 5

(B) 7

(D) 10

Answer (A) 5

Result

Reeta age = x 7

Abi age = 2x 7

Age difference = 5

2x 7 – (x 7) = 5

2x 7 – x – 7 = 5

X = 5

Which of these figures doesn’t remain the same when turned upside down?

(A) 689

(B) 66166

(D) 981186

Answer (B) 66166

Result

From left to right it’ll be as = 66166

From right to left it’ll be as = 66166

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Mathematics is the most basic quality and is employed as a part of all aspects. Students should practice Maths questions regularly to get familiarized with each topic. As we all know, Maths requires repeated practice, and therefore, students are required to practice Maths chapters regularly. To solve various types of Maths questions, students can practice previous years’ question papers and can follow Maths’s worksheets. Your brain is fine at Maths even if you aren’t. Students can systematically improve their learning of each topic by solving several Math problems delivered by ENTRI Learning App and boosting their confidence.