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As we all know, Kerala PSC exams support different topics, so there’s a chance for us to create that count. If we’ve got a logical idea about English or Maths we will be able to secure almost 35 marks with ease. which means everyone has strength on specific topics we must identify that and study accordingly. In this article, we’ll discuss Important Maths Formulas for Kerala PSC Exams
This article on Important Maths Formulas for Kerala PSC Exams will help you get extra some marks in Exams, maybe those some marks can make a difference in getting a respectable job in the Kerala Government sector.
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Important Math Formulas
- (a + b)2 = a2 + 2ab +b2
- (a+b+c)2 = a2+ b2+ c2 + 2 (ab + bc + ca)
- (a+b+c+d)2 = a2 + b2 + c2 + d2 +2 (ab + ac + ad + bc + bd + cd)
Geometry Formulas
Geometry is a branch of mathematics that deals with shape, size, the relative position of figures, and also the properties of shapes.It emerges independently in the number of early cultures as a practical way of dealing with lengths, area and volumes.
Geometry is often divided into two different types: plane geometry and solid geometry. The Plane Geometry deals with shapes such as circles, triangles, rectangles, square, and more. Whereas, the solid geometry is bothered in calculating the length, perimeter, area, and volume of varied geometric figures and shapes.
- Perimeter of a Square = P = 4a
Where a = Length of the sides of a Square
- Perimeter of a Rectangle = P = 2(l+b)
Where, l = Length ; b = Breadth
- Area of a Square = A = a2
Where a = Length of the sides of a Square
- Area of a Rectangle = A = l×b
Where, l = Length ; b = Breadth
- Area of a Triangle = A = ½×b×h
Where, b = base of the triangle; h = height of the triangle
- Area of a Trapezoid = A = ½×(b1 + b2)×h
Where b1 & b2 are the bases of the Trapezoid; h = height of the Trapezoid
- Area of a Circle = A = π×r2
- Circumference of a Circle = A = 2πr
Where, r = Radius of the Circle
- Surface Area of a Cube = S = 6a2
Where, a = Length of the sides of a Cube
- Curved surface area of a Cylinder = 2πrh
- Total surface area of a Cylinder = 2πr(r + h)
- Volume of a Cylinder = V = πr2h
Where, r = Radius of the base of the Cylinder; h = Height of the Cylinder
- Curved surface area of a cone = πrl
- Total surface area of a cone = πr(r+l) = πr[r+√(h2+r2)]
- Volume of a Cone = V = ⅓×πr2h
Where, r = Radius of the base of the Cone, h = Height of the Cone
- Surface Area of a Sphere = S = 4πr2
- Volume of a Sphere = V = 4/3×πr3
Where, r = Radius of the Sphere
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Volume
- The volume of a cube: V+a3
a: length of one side
- The volume of a box: v=l * w * h
l: length
w: width
h: height
- Volume of a sphere: v=(4/3) * ∏ * r3
∏= 3.14
r: radius of the sphere
- The volume of a cylinder: V=∏r2h
∏= 3.14
r: radius of the circle of the base
h: height of the cylinder
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